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Count Non-Decreasing Subarrays After K Operations

This problem asks you to count non-decreasing subarrays in a given array after applying at most k operations.

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Hard · Sliding window with running state updates

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Answer-first summary

This problem asks you to count non-decreasing subarrays in a given array after applying at most k operations.

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To solve this problem, efficiently count non-decreasing subarrays by utilizing a sliding window approach with state updates. Track each subarray's potential to become non-decreasing within k operations, considering operations applied to elements incrementally. The challenge involves optimizing the counting process using techniques like segment trees or sparse tables.

Problem Statement

You are given an array nums of n integers and an integer k. For each subarray of nums, you can apply up to k operations on it. In each operation, you increment any element of the subarray by 1. The goal is to count the number of non-decreasing subarrays that can be formed by performing at most k operations on the elements of the subarray.

Each subarray is considered independently, meaning changes made to one subarray do not persist to another. The challenge lies in efficiently calculating how many such non-decreasing subarrays exist after applying up to k operations, leveraging techniques like sliding windows with running state updates, segment trees, or sparse tables.

Examples

Example 1

Input: nums = [6,3,1,2,4,4], k = 7

Output: 17

Out of all 21 possible subarrays of nums , only the subarrays [6, 3, 1] , [6, 3, 1, 2] , [6, 3, 1, 2, 4] and [6, 3, 1, 2, 4, 4] cannot be made non-decreasing after applying up to k = 7 operations. Thus, the number of non-decreasing subarrays is 21 - 4 = 17 .

Example 2

Input: nums = [6,3,1,3,6], k = 4

Output: 12

The subarray [3, 1, 3, 6] along with all subarrays of nums with three or fewer elements, except [6, 3, 1] , can be made non-decreasing after k operations. There are 5 subarrays of a single element, 4 subarrays of two elements, and 2 subarrays of three elements except [6, 3, 1] , so there are 1 + 5 + 4 + 2 = 12 subarrays that can be made non-decreasing.

Constraints

  • 1 <= nums.length <= 105
  • 1 <= nums[i] <= 109
  • 1 <= k <= 109

Solution Approach

Sliding Window with State Updates

A sliding window approach is key for this problem, where we maintain a running state of the current subarray. As we iterate through the array, we update the window size, ensuring that the number of operations applied does not exceed k. If we exceed k, we shrink the window from the left side.

Efficient State Calculation with Sparse Table

To efficiently handle large arrays and minimize recalculating subarray potential, use a sparse table to store precomputed results. This will allow faster queries and updates for subarray ranges, aiding in determining which subarrays can be made non-decreasing with fewer operations.

Segment Tree Optimization

A segment tree can be used to manage the operations efficiently across multiple subarrays. This structure allows for quick range updates and queries to check if a subarray can become non-decreasing with the current operations, thereby optimizing the solution.

Complexity Analysis

Metric Value
Time Depends on the final approach
Space Depends on the final approach

The time and space complexities of the solution depend on the approach used. A basic sliding window can operate in O(n), but using a sparse table or segment tree increases the complexity to O(log n) for updates and queries. Therefore, the overall complexity depends on whether segment trees or sparse tables are utilized for efficient range queries and updates.

What Interviewers Usually Probe

  • Look for understanding of sliding window techniques and efficient state tracking.
  • Evaluate how well the candidate can optimize the solution with advanced data structures like segment trees or sparse tables.
  • Assess the candidate's ability to break down the problem into manageable sub-problems, such as determining valid subarrays and performing efficient range updates.

Common Pitfalls or Variants

Common pitfalls

  • Overcomplicating the solution without leveraging efficient data structures for range queries.
  • Forgetting that subarrays are independent of each other, which can lead to incorrect results if state is not properly reset between subarrays.
  • Not considering the impact of large values of k and the constraints on the array length, leading to time or space inefficiencies.

Follow-up variants

  • Use a sliding window without additional optimizations and handle the k operations directly.
  • Implement a solution using only the segment tree or sparse table for handling subarray checks and updates.
  • Adapt the problem for dynamic k, where the number of operations allowed per subarray can change during execution.

FAQ

How can I optimize my solution for the Count Non-Decreasing Subarrays After K Operations problem?

The optimal approach combines sliding windows with state updates and efficient range queries using segment trees or sparse tables.

What is the time complexity of a solution that uses a sliding window for this problem?

A basic sliding window solution can have a time complexity of O(n), but using additional data structures like sparse tables or segment trees will optimize it further.

What is a sliding window with state updates in this context?

It is a technique where you maintain a window of subarray elements and dynamically adjust it, ensuring that the subarray meets the condition of being non-decreasing after at most k operations.

How does using a sparse table help in this problem?

A sparse table helps by precomputing results for ranges, which speeds up queries and updates, making it ideal for handling subarrays efficiently.

Can this problem be solved without using advanced data structures?

While it is possible to solve the problem without advanced data structures, using structures like segment trees or sparse tables significantly improves the efficiency, especially for larger arrays.

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Solution

Solution 1

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