LeetCode Problem Workspace
Sum of Nodes with Even-Valued Grandparent
This problem involves calculating the sum of nodes with an even-valued grandparent in a binary tree.
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Practice Focus
Medium · Binary-tree traversal and state tracking
Answer-first summary
This problem involves calculating the sum of nodes with an even-valued grandparent in a binary tree.
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To solve this, you must traverse the tree while keeping track of both parent and grandparent nodes. The challenge lies in efficiently summing nodes based on an even-valued grandparent. This can be achieved through a depth-first traversal or breadth-first search, ensuring you maintain state information for each node visited.
Problem Statement
You are given the root of a binary tree. The task is to return the sum of values of the nodes with an even-valued grandparent. If no nodes have an even-valued grandparent, return 0. A grandparent of a node is defined as the parent of its parent, if it exists.
To solve this, you need to efficiently traverse the tree while keeping track of both the parent and grandparent nodes. During traversal, sum the node values when the grandparent has an even value. The traversal can be done using depth-first or breadth-first search techniques.
Examples
Example 1
Input: root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5]
Output: 18
The red nodes are the nodes with even-value grandparent while the blue nodes are the even-value grandparents.
Example 2
Input: root = [1]
Output: 0
Example details omitted.
Constraints
- The number of nodes in the tree is in the range [1, 104].
- 1 <= Node.val <= 100
Solution Approach
Tree Traversal with State Tracking
Start by traversing the tree, keeping track of the current node, its parent, and its grandparent. For each node, check if the grandparent has an even value, and if so, add the current node's value to the sum.
Depth-First Search (DFS)
DFS is a natural choice for this problem as it allows you to explore each node while maintaining the state of parent and grandparent. Use recursion to move down the tree while passing state information along the way.
Breadth-First Search (BFS)
Alternatively, use BFS for an iterative approach. Track parent and grandparent nodes as you traverse level by level. This method can be more suitable for certain tree structures but still requires careful state management.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | O(N) |
| Space | O(N) |
The time complexity of this solution is O(N), where N is the number of nodes in the tree. This is because each node is visited exactly once. The space complexity is also O(N) due to the need to store state information for each node during traversal, especially for DFS when recursion is used, or for BFS when the queue stores nodes.
What Interviewers Usually Probe
- Ability to keep track of state while traversing the tree.
- Efficient use of tree traversal techniques, either DFS or BFS.
- Clear understanding of parent-child relationships and their role in tree traversal.
Common Pitfalls or Variants
Common pitfalls
- Failing to properly maintain the state of parent and grandparent nodes during traversal.
- Not considering edge cases such as a tree with only one node or no even-valued grandparents.
- Using a non-optimal tree traversal technique that leads to unnecessary complexity or memory usage.
Follow-up variants
- Modify the problem to sum nodes with odd-valued grandparents.
- Add a constraint that the tree is balanced or sorted in some way.
- Consider different tree types, such as AVL or Red-Black trees, and adapt the traversal accordingly.
FAQ
How do I handle state tracking in the 'Sum of Nodes with Even-Valued Grandparent' problem?
Maintain the current node, its parent, and its grandparent during the tree traversal. This ensures that the sum is only calculated when the grandparent is even.
What traversal method should I use for 'Sum of Nodes with Even-Valued Grandparent'?
Both DFS and BFS are suitable. DFS is often more straightforward for recursive approaches, while BFS can be useful for iterative traversal.
What are the time and space complexities for this problem?
The time complexity is O(N), and the space complexity is also O(N) due to the need to store information about the parent and grandparent during traversal.
Can I solve this problem using iterative methods?
Yes, you can use BFS for an iterative approach, where the state of parent and grandparent is tracked at each level of traversal.
Are there edge cases I should consider for this problem?
Yes, consider cases such as a tree with only one node or a tree where no nodes have an even-valued grandparent.
Solution
Solution 1: DFS
We design a function $dfs(root, x)$, which represents the sum of the values of the nodes that meet the conditions in the subtree with $root$ as the root node and $x$ as the value of the parent node of $root$. The answer is $dfs(root, 1)$.
# Definition for a binary tree node.
# class TreeNode:
# def __init__(self, val=0, left=None, right=None):
# self.val = val
# self.left = left
# self.right = right
class Solution:
def sumEvenGrandparent(self, root: TreeNode) -> int:
def dfs(root: TreeNode, x: int) -> int:
if root is None:
return 0
ans = dfs(root.left, root.val) + dfs(root.right, root.val)
if x % 2 == 0:
if root.left:
ans += root.left.val
if root.right:
ans += root.right.val
return ans
return dfs(root, 1)Continue Topic
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