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Maximum Value Sum by Placing Three Rooks II

Maximize the sum by placing three non-attacking rooks on a chessboard with dynamic programming.

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Hard · State transition dynamic programming

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Answer-first summary

Maximize the sum by placing three non-attacking rooks on a chessboard with dynamic programming.

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The goal is to place three rooks on a chessboard such that they do not attack each other, maximizing the sum of their values. This problem relies on dynamic programming, using state transitions to explore valid placements efficiently. It tests the ability to utilize row-based value maximization with a focus on minimizing attacks between rooks.

Problem Statement

You are given an m x n 2D array, board, representing a chessboard, where each element, board[i][j], is the value of the cell (i, j). Your task is to place three rooks on this chessboard such that no two rooks attack each other. Rooks can only attack each other if they share the same row or column.

Return the maximum sum of the cell values where the three rooks are placed. It is guaranteed that the board has at least three cells, and the values range from -109 to 109. The problem requires you to efficiently solve this using dynamic programming with a state transition approach.

Examples

Example 1

Input: board = [[-3,1,1,1],[-3,1,-3,1],[-3,2,1,1]]

Output: 4

We can place the rooks in the cells (0, 2) , (1, 3) , and (2, 1) for a sum of 1 + 1 + 2 = 4 .

Example 2

Input: board = [[1,2,3],[4,5,6],[7,8,9]]

Output: 15

We can place the rooks in the cells (0, 0) , (1, 1) , and (2, 2) for a sum of 1 + 5 + 9 = 15 .

Example 3

Input: board = [[1,1,1],[1,1,1],[1,1,1]]

Output: 3

We can place the rooks in the cells (0, 2) , (1, 1) , and (2, 0) for a sum of 1 + 1 + 1 = 3 .

Constraints

  • 3 <= m == board.length <= 500
  • 3 <= n == board[i].length <= 500
  • -109 <= board[i][j] <= 109

Solution Approach

Dynamic Programming with Row-Wise Maximization

We solve this problem using dynamic programming, iterating through the chessboard's rows. For each row, we compute the three highest values and track them. This allows us to efficiently place one rook in each row, without violating the attack condition, while maximizing the sum of the selected values.

State Transitions Between Rows

The solution applies state transition principles by calculating the best rook placements for each row while considering previous row placements. The idea is to keep track of the maximum values for every combination of rows and columns, which helps avoid unnecessary recomputation and reduces complexity.

Final Optimization and Result Calculation

Once we've built the dynamic programming table, the final step is to combine the results of different row combinations. By selecting the best placement for each rook across the rows, we can obtain the maximum sum. This requires careful iteration to ensure no two rooks are placed in the same row or column.

Complexity Analysis

Metric Value
Time Depends on the final approach
Space Depends on the final approach

The time complexity depends on the number of rows and columns, as well as the way we transition between states. A naive approach could lead to O(m * n^2), but using dynamic programming optimizes this to O(m * n), where m is the number of rows and n is the number of columns. Space complexity similarly depends on the number of states we store for each row, leading to O(m * n) space usage.

What Interviewers Usually Probe

  • Check if the candidate can identify the dynamic programming nature of this problem.
  • Evaluate the candidate's understanding of row-wise maximization and state transitions.
  • Observe the candidate's ability to optimize space complexity while maintaining efficiency.

Common Pitfalls or Variants

Common pitfalls

  • Failing to track the top three values in each row and revisiting the same values repeatedly.
  • Not handling row and column uniqueness correctly, leading to invalid rook placements.
  • Overcomplicating the solution by attempting brute force instead of utilizing dynamic programming optimizations.

Follow-up variants

  • Increasing the number of rooks to be placed, which adds complexity to the dynamic programming approach.
  • Considering different board sizes, such as a larger m x n array, to challenge the space and time optimizations.
  • Allowing for variable rook placements, where more complex rules determine valid positions, still using dynamic programming.

FAQ

How can I maximize the sum of rook placements in the Maximum Value Sum by Placing Three Rooks II problem?

The optimal approach involves dynamic programming where you track the top three values in each row and compute state transitions across rows to maximize the sum.

What is the time complexity of solving the Maximum Value Sum by Placing Three Rooks II problem?

The time complexity is O(m * n) due to the dynamic programming approach, where m is the number of rows and n is the number of columns.

Can the Maximum Value Sum by Placing Three Rooks II problem be solved without dynamic programming?

While it's possible to attempt brute force, dynamic programming significantly optimizes the process by reducing repeated computations and minimizing time complexity.

What should I focus on while solving the Maximum Value Sum by Placing Three Rooks II problem in an interview?

Focus on understanding the state transition dynamic programming pattern and optimizing both time and space complexity.

How does GhostInterview help with the Maximum Value Sum by Placing Three Rooks II problem?

GhostInterview assists by providing detailed guidance on solving this problem, highlighting key concepts like dynamic programming, state transitions, and common pitfalls.

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Solution

Solution 1

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Maximum Value Sum by Placing Three Rooks II Solution: State transition dynamic programming | LeetCode #3257 Hard