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Maximum Value Sum by Placing Three Rooks I
Maximize the value sum by placing three rooks on a chessboard while ensuring they do not attack each other.
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Hard · State transition dynamic programming
Answer-first summary
Maximize the value sum by placing three rooks on a chessboard while ensuring they do not attack each other.
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In this problem, we need to place three rooks on a chessboard so that no two rooks attack each other. Using dynamic programming, we aim to maximize the sum of the cell values on which the rooks are placed, leveraging the board's row and column constraints.
Problem Statement
You are given a m x n 2D array board representing a chessboard, where each element board[i][j] indicates the value of the cell at row i, column j. You need to place three rooks on the board such that no two rooks attack each other. Rooks in the same row or column are considered to be attacking each other. Your task is to return the maximum sum of the values from the cells where the rooks are placed.
The board can have dimensions of 3x3 or larger, and the values in the cells can range from -10^9 to 10^9. You must ensure the rooks are placed in a way that maximizes the sum of the selected cells while adhering to the attack constraints.
Examples
Example 1
Input: board = [[-3,1,1,1],[-3,1,-3,1],[-3,2,1,1]]
Output: 4
We can place the rooks in the cells (0, 2) , (1, 3) , and (2, 1) for a sum of 1 + 1 + 2 = 4 .
Example 2
Input: board = [[1,2,3],[4,5,6],[7,8,9]]
Output: 15
We can place the rooks in the cells (0, 0) , (1, 1) , and (2, 2) for a sum of 1 + 5 + 9 = 15 .
Example 3
Input: board = [[1,1,1],[1,1,1],[1,1,1]]
Output: 3
We can place the rooks in the cells (0, 2) , (1, 1) , and (2, 0) for a sum of 1 + 1 + 1 = 3 .
Constraints
- 3 <= m == board.length <= 100
- 3 <= n == board[i].length <= 100
- -109 <= board[i][j] <= 109
Solution Approach
Dynamic Programming with State Transition
We will use dynamic programming to find the optimal placement of three rooks. The state transition will involve keeping track of the largest values available in each row and column, ensuring that no two rooks occupy the same row or column. By storing the best possible choices for each step, we can compute the optimal solution efficiently.
Enumeration of Possible Placements
Enumerating the possible placements of rooks in different rows and columns is crucial. By selecting the largest values from each row while keeping track of column constraints, we ensure that the solution explores the best combination of placements. The enumeration method reduces the complexity of directly computing all possibilities.
Optimization Using Row Constraints
To optimize the solution, we can store the largest 3 values for each row, reducing the number of computations required. This approach ensures that we are working with the highest potential cell values, making the search for the best placements faster and more efficient.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | Depends on the final approach |
| Space | Depends on the final approach |
The time and space complexity depend on the final approach, but typically it will be O(m * n) where m is the number of rows and n is the number of columns in the board. The solution uses dynamic programming to store state transitions, reducing redundant calculations.
What Interviewers Usually Probe
- Assess the candidate's understanding of dynamic programming and state transitions in grid-based problems.
- Evaluate the ability to manage constraints like row and column restrictions when placing objects on a grid.
- Look for clear reasoning behind optimizing the search for the best rook placements using pre-calculated values.
Common Pitfalls or Variants
Common pitfalls
- Failing to properly handle row and column restrictions, leading to incorrect placements.
- Overlooking edge cases, such as negative values in the board or having too few rows and columns.
- Not optimizing by storing the largest values, leading to unnecessary recalculations and inefficiencies.
Follow-up variants
- Instead of three rooks, consider placing a different number of rooks, adjusting the dynamic programming approach accordingly.
- Extend the problem to larger boards with more rows and columns, requiring more sophisticated optimizations.
- Introduce varying rook values or constraints to test the algorithm's adaptability to different scenarios.
FAQ
How do I maximize the value sum when placing three rooks on the board?
You need to use dynamic programming to keep track of the largest values in each row and column while ensuring no rooks attack each other. The solution should explore optimal placements that maximize the sum of the selected cells.
What is the time complexity of solving the Maximum Value Sum by Placing Three Rooks I?
The time complexity typically depends on the dynamic programming approach used, often O(m * n) where m is the number of rows and n is the number of columns in the board.
Can I place more than three rooks on the board?
Yes, this problem can be extended to place more than three rooks. However, the dynamic programming approach would need to account for additional rooks and the corresponding constraints.
What is the best way to handle negative values on the chessboard?
You should still apply dynamic programming, but ensure your solution accounts for the possibility of negative values when selecting rook placements to maximize the sum.
How does dynamic programming help in solving the problem?
Dynamic programming helps by storing intermediate results and state transitions, reducing redundant calculations and efficiently finding the best rook placements.
Solution
Solution 1
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