#1172

Hard

auto_awesomeStack-based state management

LeetCode Problem Workspace

Dinner Plate Stacks

Design a system that manages dinner plate stacks using stack-based state management, handling dynamic plate placement and retrieval.

hash table stack design heap priority queue

Problem Statement

You are tasked with implementing the DinnerPlates class that manages an infinite number of stacks, each with a fixed maximum capacity. The class should support pushing and popping dinner plates across multiple stacks, while ensuring that each stack never exceeds its capacity.

Additionally, you need to implement a feature to pop a plate from a specific stack index. The problem emphasizes efficient stack-based state management, where tracking of vacant spots and ensuring quick retrieval and placement is key. The design requires the use of data structures like hash tables and heaps for optimal performance.

Examples

Example 1

Input: See original problem statement.

Output: See original problem statement.

DinnerPlates D = DinnerPlates(2); // Initialize with capacity = 2 D.push(1); D.push(2); D.push(3); D.push(4); D.push(5); // The stacks are now: 2 4 1 3 5 ﹈﹈﹈ D.popAtStack(0); // Returns 2. The stacks are now: 4 1 3 5 ﹈﹈﹈ D.push(20); // The stacks are now: 20 4 1 3 5 ﹈﹈﹈ D.push(21); // The stacks are now: 20 4 21 1 3 5 ﹈﹈﹈ D.popAtStack(0); // Returns 20. The stacks are now: 4 21 1 3 5 ﹈﹈﹈ D.popAtStack(2); // Returns 21. The stacks are now: 4 1 3 5 ﹈﹈﹈ D.pop() // Returns 5. The stacks are now: 4 1 3 ﹈﹈ D.pop() // Returns 4. The stacks are now: 1 3 ﹈﹈ D.pop() // Returns 3. The stacks are now: 1 ﹈ D.pop() // Returns 1. There are no stacks. D.pop() // Returns -1. There are still no stacks.

Constraints

1 <= capacity <= 2 * 104
1 <= val <= 2 * 104
0 <= index <= 105
At most 2 * 105 calls will be made to push, pop, and popAtStack.

Solution Approach

Use Hash Table for Stack Management

To efficiently manage multiple stacks, use a hash table to map stack indices to their corresponding plate values. This allows for fast lookups when handling operations like push and popAtStack. The hash table will maintain the state of each stack dynamically.

Track Vacant Stacks with a Heap

To efficiently handle stack vacancies, a heap can be used to track the leftmost vacant stack. This ensures that push operations are directed to the earliest available stack, minimizing stack usage and improving overall performance.

Optimizing Pop Operations

For popAtStack and pop operations, iterate over the corresponding stack efficiently and update the stack state using the hash table and heap. Special attention is given to ensuring minimal complexity during pop operations to maintain optimal time and space efficiency.

Complexity Analysis

Metric	Value
Time	Depends on the final approach
Space	Depends on the final approach

The time complexity for push operations is O(log n) due to heap operations, while popAtStack may take O(log n) in the worst case. The space complexity depends on the number of plates and stacks being managed, primarily influenced by the use of the hash table and heap for storage.

What Interviewers Usually Probe

Evaluates candidate's ability to design systems with dynamic state management.
Tests problem-solving with hash tables and heaps in stack operations.
Assesses efficiency in handling push, pop, and popAtStack with large input sizes.

Common Pitfalls or Variants

Common pitfalls

Not efficiently tracking vacant stacks leading to slow push operations.
Improper handling of edge cases when stacks are empty or nearly full.
Excessive complexity in the popAtStack function that impacts performance.

Follow-up variants

Implement a version where the stack sizes are dynamic instead of fixed.
Extend the problem to allow resizing of stacks during execution.
Optimize for handling larger datasets by minimizing the time complexity of popAtStack.

FAQ

How do you efficiently manage multiple stacks in the Dinner Plate Stacks problem?

Efficient management involves using a hash table to store stack states and a heap to track vacant stacks, minimizing the time complexity for push operations.

What is the key challenge in handling popAtStack?

The challenge is efficiently identifying the correct stack to pop from and ensuring minimal complexity when modifying the state of the stack.

What are the performance considerations for large datasets in this problem?

The primary performance concern is minimizing the time complexity for popAtStack operations, especially in scenarios with many stacks and large numbers of operations.

How can you optimize the Dinner Plates solution?

Optimizing involves using a heap to efficiently track vacant stacks and ensuring quick lookups for both push and popAtStack operations using a hash table.

What is the stack-based state management pattern in this problem?

The stack-based state management pattern involves tracking the current state of each stack, including whether it's full or vacant, and managing operations like push and pop efficiently using appropriate data structures.

terminal

Solution

Solution 1: Stack Array + Ordered Set

We define the following data structures or variables:

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class DinnerPlates:
    def __init__(self, capacity: int):
        self.capacity = capacity
        self.stacks = []
        self.not_full = SortedSet()

    def push(self, val: int) -> None:
        if not self.not_full:
            self.stacks.append([val])
            if self.capacity > 1:
                self.not_full.add(len(self.stacks) - 1)
        else:
            index = self.not_full[0]
            self.stacks[index].append(val)
            if len(self.stacks[index]) == self.capacity:
                self.not_full.discard(index)

    def pop(self) -> int:
        return self.popAtStack(len(self.stacks) - 1)

    def popAtStack(self, index: int) -> int:
        if index < 0 or index >= len(self.stacks) or not self.stacks[index]:
            return -1
        val = self.stacks[index].pop()
        if index == len(self.stacks) - 1 and not self.stacks[-1]:
            while self.stacks and not self.stacks[-1]:
                self.not_full.discard(len(self.stacks) - 1)
                self.stacks.pop()
        else:
            self.not_full.add(index)
        return val


# Your DinnerPlates object will be instantiated and called as such:
# obj = DinnerPlates(capacity)
# obj.push(val)
# param_2 = obj.pop()
# param_3 = obj.popAtStack(index)

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