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Poor Pigs
Find the minimum number of pigs required to determine the poisonous bucket within a set time using state transition dynamic programming.
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Practice Focus
Hard · State transition dynamic programming
Answer-first summary
Find the minimum number of pigs required to determine the poisonous bucket within a set time using state transition dynamic programming.
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In the Poor Pigs problem, you need to find the minimum number of pigs needed to identify a poisonous bucket within a given time. The solution involves using dynamic programming to model state transitions, considering the number of pigs, test time, and the number of buckets. The key pattern revolves around calculating the different outcomes of pig death scenarios at the end of each testing period.
Problem Statement
Given buckets buckets of liquid, one of which is poisonous, you have a limited number of pigs to figure out which bucket contains the poison. Each pig can be fed liquid from a set of buckets, and you can observe whether the pig dies or not after a specific time. You have exactly minutesToTest minutes to figure out which bucket is poisonous, but each pig dies after minutesToDie minutes if they drink from the poisonous bucket.
Your task is to return the minimum number of pigs required to determine which bucket is poisonous within the given minutesToTest time frame. The challenge involves balancing the number of pigs with the time constraints to optimize the test outcomes.
Examples
Example 1
Input: buckets = 4, minutesToDie = 15, minutesToTest = 15
Output: 2
We can determine the poisonous bucket as follows: At time 0, feed the first pig buckets 1 and 2, and feed the second pig buckets 2 and 3. At time 15, there are 4 possible outcomes:
- If only the first pig dies, then bucket 1 must be poisonous.
- If only the second pig dies, then bucket 3 must be poisonous.
- If both pigs die, then bucket 2 must be poisonous.
- If neither pig dies, then bucket 4 must be poisonous.
Example 2
Input: buckets = 4, minutesToDie = 15, minutesToTest = 30
Output: 2
We can determine the poisonous bucket as follows: At time 0, feed the first pig bucket 1, and feed the second pig bucket 2. At time 15, there are 2 possible outcomes:
- If either pig dies, then the poisonous bucket is the one it was fed.
- If neither pig dies, then feed the first pig bucket 3, and feed the second pig bucket 4. At time 30, one of the two pigs must die, and the poisonous bucket is the one it was fed.
Constraints
- 1 <= buckets <= 1000
- 1 <= minutesToDie <= minutesToTest <= 100
Solution Approach
State Transition Dynamic Programming
The problem revolves around state transitions where the state is defined by which pigs are alive after each test. Each pig has multiple possible outcomes: dead or alive after a test period. This can be modeled as a state transition problem, where the number of pigs is incrementally tested by simulating different bucket-pig pairings to reduce the search space. The idea is to use dynamic programming to calculate the minimum pigs required for a given number of buckets and time constraints.
Combinatorics and Outcomes
Given that each pig can have multiple possible outcomes (alive or dead), the total number of outcomes after each test period increases exponentially. To optimize the number of pigs, we consider the possible outcomes of each pig and their combinations over multiple rounds of testing. This approach uses combinatorics to calculate the number of possible outcomes for each combination of pigs and buckets, helping to minimize the number of pigs needed.
Binary Representation of Outcomes
The state transition for each test round can be represented in binary form, where each bit indicates whether a pig survives or dies. By mapping the outcomes of each test round to a binary representation, we can use binary search principles to efficiently determine the minimum number of pigs. This allows for an optimized decision-making process when allocating pigs to buckets, ensuring the problem's constraints are met.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | Depends on the final approach |
| Space | Depends on the final approach |
The time and space complexity of this problem depend on the approach used for dynamic programming and the number of pigs required. In the worst case, the space complexity grows with the number of pigs and buckets, as we need to store the state transitions for each test. The time complexity is dominated by the need to calculate outcomes for each combination of pigs and buckets, which can be exponential in nature, leading to higher complexities for larger inputs.
What Interviewers Usually Probe
- Look for the candidate's understanding of state transition problems in dynamic programming.
- Evaluate how well the candidate applies combinatorics to optimize the problem solution.
- Check for a clear explanation of how binary representation is used to model outcomes.
Common Pitfalls or Variants
Common pitfalls
- Not considering the optimal distribution of pigs across buckets, leading to unnecessary pigs for fewer buckets.
- Overcomplicating the problem by not using binary or combinatorial representations effectively.
- Failing to account for the time constraints and misjudging how many pigs are needed based on the number of test rounds.
Follow-up variants
- Increasing the number of buckets or test time constraints to assess scalability of the approach.
- Allowing pigs to be reused across multiple tests, which changes the dynamic of how the problem is solved.
- Introducing more than one poisonous bucket, requiring more sophisticated state transition models.
FAQ
How can I approach the Poor Pigs problem with dynamic programming?
Dynamic programming is key in Poor Pigs as it models the state transitions of pigs dying or surviving based on test outcomes. You calculate the minimum pigs required by considering each possible outcome and optimizing with combinatorial logic.
What is the best way to minimize pigs for the Poor Pigs problem?
The optimal strategy involves using binary representations to model the outcomes of each pig's death or survival. This reduces the number of pigs needed to cover all possible outcomes, ensuring efficiency.
How does the number of test rounds impact the number of pigs?
Each round of testing increases the number of possible outcomes exponentially. Balancing the pigs across these rounds optimally minimizes the total number of pigs needed, leveraging combinatorial strategies.
What if I have more than one poisonous bucket?
If multiple poisonous buckets are involved, the problem becomes more complex, and the approach needs to adapt by considering multiple outcomes at each test point, requiring more advanced dynamic programming techniques.
Can GhostInterview help me solve the Poor Pigs problem step-by-step?
Yes, GhostInterview provides a structured walkthrough of the Poor Pigs problem, breaking it down into manageable steps, ensuring that you understand both the theory and application of the solution.
Solution
Solution 1
#### Python3
class Solution:
def poorPigs(self, buckets: int, minutesToDie: int, minutesToTest: int) -> int:
base = minutesToTest // minutesToDie + 1
res, p = 0, 1
while p < buckets:
p *= base
res += 1
return resContinue Topic
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