LeetCode Problem Workspace
Lexicographically Smallest String After Adjacent Removals
Find the lexicographically smallest string by repeatedly removing adjacent characters optimally using dynamic programming transitions.
2
Topics
0
Code langs
3
Related
Practice Focus
Hard · State transition dynamic programming
Answer-first summary
Find the lexicographically smallest string by repeatedly removing adjacent characters optimally using dynamic programming transitions.
Ace coding interviews with Interview AiBoxInterview AiBox guidance for State transition dynamic programming
This problem requires reducing a string to its lexicographically smallest form through repeated adjacent character removals. Using a state transition dynamic programming approach ensures you track minimal outcomes at each step. The key is efficiently managing substring combinations to avoid redundant computations while guaranteeing the smallest possible final string.
Problem Statement
Given a string s containing only lowercase English letters, you can remove adjacent characters any number of times, including zero. Each removal may create new adjacent pairs, and the process can be repeated optimally.
Return the lexicographically smallest string achievable after applying these adjacent removals. Ensure that every choice considers potential future removals to minimize the final string.
Examples
Example 1
Input: s = "abc"
Output: "a"
Example 2
Input: s = "bcda"
Output: ""
Example 3
Input: s = "zdce"
Output: "zdce"
Constraints
- 1 <= s.length <= 250
- s consists only of lowercase English letters.
Solution Approach
Dynamic Programming State Definition
Define dp[i][j] as the lexicographically smallest string obtainable from the substring s[i..j]. Each state considers whether to remove an adjacent pair or leave it, capturing all minimal outcomes.
Transition Between States
Iterate over all possible partitions within the substring. For each split, compute the minimal string by combining left and right subresults. Update dp[i][j] with the smallest lexicographic option. Carefully handle newly adjacent characters created after removals.
Final String Extraction
After filling the dp table, dp[0][n-1] holds the answer for the entire string. This captures all optimal removal sequences and guarantees the lexicographically smallest result.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | Depends on the final approach |
| Space | Depends on the final approach |
Time complexity depends on substring splits and combinations, roughly O(n^3) for DP over length n. Space complexity is O(n^2) for storing minimal results for all substrings.
What Interviewers Usually Probe
- Check if you considered all possible adjacent removal sequences.
- Notice if your DP correctly handles new adjacent pairs after a removal.
- Evaluate whether your state transitions guarantee lexicographically minimal results.
Common Pitfalls or Variants
Common pitfalls
- Ignoring new adjacent pairs formed after a removal and missing further reductions.
- Incorrectly comparing strings lexicographically leading to non-minimal results.
- Overlooking overlapping subproblems, causing redundant computation and slow performance.
Follow-up variants
- Restrict removal to identical adjacent characters only, changing DP transitions.
- Compute lexicographically largest string instead, requiring inverted comparison logic.
- Limit maximum number of removals, introducing additional state tracking in DP.
FAQ
What is the core pattern in Lexicographically Smallest String After Adjacent Removals?
The key pattern is state transition dynamic programming, tracking minimal strings across all substrings as adjacent characters are removed.
How do I handle newly adjacent characters after a removal?
Update your DP states to consider the resulting adjacent characters and recompute minimal substrings including them.
Can this problem be solved greedily instead of DP?
A greedy approach may fail because local removal decisions might not yield a globally minimal string; DP ensures all combinations are considered.
What is the time complexity for large strings?
Time complexity is approximately O(n^3) due to evaluating all substrings and partitions for DP, and space complexity is O(n^2).
Are there simpler variations of this problem?
Yes, variations include restricting removals to identical characters, or computing the lexicographically largest string instead.
Solution
Solution 1
#### Python3
Continue Topic
string
Practice more edge cases under the same topic.
arrow_forwardauto_awesomeContinue Pattern
State transition dynamic programming
Expand the same solving frame across more problems.
arrow_forwardsignal_cellular_altSame Difficulty Track
Hard
Stay on this level to stabilize interview delivery.
arrow_forward