#299

Medium

LeetCode Problem Workspace

Bulls and Cows

Solve the Bulls and Cows problem using hash tables and string manipulation to track exact and misplaced digits.

Problem Statement

You are playing a game with a secret number and your friend’s guess. The goal is to provide feedback about how close the guess is to the secret number. The feedback should consist of two numbers: the number of bulls and the number of cows. A bull is a digit that is in the correct position, while a cow is a digit that exists in the secret but is in the wrong position.

Given two strings, secret and guess, both representing the secret number and the guessed number respectively, return a string hint of the form 'xAyB', where 'x' is the number of bulls and 'y' is the number of cows. You need to consider digits that appear in both secret and guess, ensuring efficient counting of misplaced digits.

Examples

Example 1

Input: secret = "1807", guess = "7810"

Output: "1A3B"

Bulls are connected with a '|' and cows are underlined: "1807" | "7810"

Example 2

Input: secret = "1123", guess = "0111"

Output: "1A1B"

Bulls are connected with a '|' and cows are underlined: "1123" "1123" | or | "0111" "0111" Note that only one of the two unmatched 1s is counted as a cow since the non-bull digits can only be rearranged to allow one 1 to be a bull.

Constraints

1 <= secret.length, guess.length <= 1000
secret.length == guess.length
secret and guess consist of digits only.

Solution Approach

Count Exact Matches (Bulls)

First, iterate through both secret and guess strings. For each digit that matches at the same index, increase the bull count. This step is straightforward and provides a direct way to track exact matches.

Count Misplaced Digits (Cows)

After counting the bulls, a hash table can be used to count the frequency of unmatched digits in both secret and guess. For each unmatched digit in guess, check if it exists in the hash table of secret and count it as a cow if it does. This allows for an efficient count of misplaced digits.

Edge Case Handling

Make sure to handle edge cases like when secret and guess contain the same repeated digits. For example, '1122' and '2211' should be carefully processed to ensure only the correct number of cows are counted, without overcounting any digits.

Complexity Analysis

Metric	Value
Time	Depends on the final approach
Space	Depends on the final approach

The time complexity is O(n), where n is the length of the strings secret and guess, because we are iterating through the strings to count bulls and cows. The space complexity is O(1) in terms of extra space, assuming the hash table for counting digit frequencies uses a fixed-size array for digits 0-9.

What Interviewers Usually Probe

Does the candidate consider both bulls and cows efficiently?
How well does the candidate handle edge cases like repeated digits in both secret and guess?
Can the candidate discuss time and space complexities clearly in relation to hash tables?

Common Pitfalls or Variants

Common pitfalls

Failing to properly account for repeated digits can lead to incorrect cow counts.
Using a brute force approach for comparing all digits without using a hash table can significantly increase time complexity.
Not handling edge cases like when all digits are bulls or cows could result in missed cases.

Follow-up variants

Consider a version where the strings have different lengths, adding a validation step before proceeding.
Modify the problem to work with non-digit strings, such as alphanumeric characters.
Incorporate a timing constraint to optimize the solution's performance under time limits.

FAQ

What is the core approach to solving the Bulls and Cows problem?

The core approach to solving Bulls and Cows is using hash tables to efficiently count and match digits in both the secret and guess strings.

How do bulls and cows differ in the context of this problem?

Bulls are digits that match both in value and position between the secret and guess, while cows are digits that match in value but are in the wrong position.

Why is using a hash table critical in this problem?

A hash table allows for efficient counting of digit frequencies, which is essential for accurately counting cows while keeping the time complexity manageable.

How do you handle repeated digits when calculating cows?

When handling repeated digits, ensure that cows are counted only for unmatched digits that are available in the secret. Be mindful of the number of occurrences in both strings to avoid overcounting.

What is the expected time complexity for solving Bulls and Cows?

The expected time complexity is O(n), where n is the length of the strings, as we process each character once to count bulls and cows.

terminal

Solution

Solution 1: Counting

We create two counters, $cnt1$ and $cnt2$, to count the occurrence of each digit in the secret number and the friend's guess respectively. At the same time, we create a variable $x$ to count the number of bulls.

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class Solution:
    def getHint(self, secret: str, guess: str) -> str:
        cnt1, cnt2 = Counter(), Counter()
        x = 0
        for a, b in zip(secret, guess):
            if a == b:
                x += 1
            else:
                cnt1[a] += 1
                cnt2[b] += 1
        y = sum(min(cnt1[c], cnt2[c]) for c in cnt1)
        return f"{x}A{y}B"

Continue Practicing

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