LeetCode 题解工作台
有效的数独
请你判断一个 9 x 9 的数独是否有效。只需要 根据以下规则 ,验证已经填入的数字是否有效即可。 数字 1-9 在每一行只能出现一次。 数字 1-9 在每一列只能出现一次。 数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。(请参考示例图) 注意: 一个有效的数独(部分已被填充)不一…
3
题型
9
代码语言
3
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答案摘要
有效的数独满足以下三个条件: - 每一行中的数字都不重复;
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题目描述
请你判断一个 9 x 9 的数独是否有效。只需要 根据以下规则 ,验证已经填入的数字是否有效即可。
- 数字
1-9在每一行只能出现一次。 - 数字
1-9在每一列只能出现一次。 - 数字
1-9在每一个以粗实线分隔的3x3宫内只能出现一次。(请参考示例图)
注意:
- 一个有效的数独(部分已被填充)不一定是可解的。
- 只需要根据以上规则,验证已经填入的数字是否有效即可。
- 空白格用
'.'表示。
示例 1:
输入:board = [["5","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] 输出:true
示例 2:
输入:board = [["8","3",".",".","7",".",".",".","."] ,["6",".",".","1","9","5",".",".","."] ,[".","9","8",".",".",".",".","6","."] ,["8",".",".",".","6",".",".",".","3"] ,["4",".",".","8",".","3",".",".","1"] ,["7",".",".",".","2",".",".",".","6"] ,[".","6",".",".",".",".","2","8","."] ,[".",".",".","4","1","9",".",".","5"] ,[".",".",".",".","8",".",".","7","9"]] 输出:false 解释:除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。 但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。
提示:
board.length == 9board[i].length == 9board[i][j]是一位数字(1-9)或者'.'
解题思路
方法一:一次遍历
有效的数独满足以下三个条件:
- 每一行中的数字都不重复;
- 每一列中的数字都不重复;
- 每一个 的宫格中的数字都不重复。
遍历数独,对于每个数字,判断其所在的行、列 以及 的宫格是否已经出现过该数字,如果是,则返回 false。遍历结束,返回 true。
时间复杂度 ,空间复杂度 ,其中 是数独中的空格数。本题中 。
class Solution:
def isValidSudoku(self, board: List[List[str]]) -> bool:
row = [[False] * 9 for _ in range(9)]
col = [[False] * 9 for _ in range(9)]
sub = [[False] * 9 for _ in range(9)]
for i in range(9):
for j in range(9):
c = board[i][j]
if c == '.':
continue
num = int(c) - 1
k = i // 3 * 3 + j // 3
if row[i][num] or col[j][num] or sub[k][num]:
return False
row[i][num] = True
col[j][num] = True
sub[k][num] = True
return True
复杂度分析
| 指标 | 值 |
|---|---|
| 时间 | Depends on the final approach |
| 空间 | Depends on the final approach |
面试官常问的追问
外企场景- question_mark
Do you recognize how duplicate checks in rows, columns, and sub-boxes can be optimized using hash sets?
- question_mark
Can you map each board cell to its 3x3 sub-box index without extra loops?
- question_mark
Will you handle empty cells efficiently to avoid unnecessary hash operations?
常见陷阱
外企场景- error
Confusing the 3x3 sub-box indexing, which can lead to missed duplicates or false positives.
- error
Checking only rows and columns but forgetting sub-boxes, which breaks Sudoku rules.
- error
Attempting to scan sub-boxes with nested loops for every cell instead of using precomputed hash sets, causing redundant computations.
进阶变体
外企场景- arrow_right_alt
Determine the minimum changes required to make a partially filled Sudoku board valid.
- arrow_right_alt
Validate a Sudoku board of arbitrary size N x N with sqrt(N) x sqrt(N) sub-boxes.
- arrow_right_alt
Implement a Sudoku solver that fills empty cells while maintaining validity at each step.