LeetCode 题解工作台
最大数
给定一组非负整数 nums ,重新排列每个数的顺序(每个数不可拆分)使之组成一个最大的整数。 注意: 输出结果可能非常大,所以你需要返回一个字符串而不是整数。 示例 1: 输入 : nums = [10,2] 输出: "210" 示例 2: 输入 : nums = [3,30,34,5,9] 输出:…
4
题型
7
代码语言
3
相关题
当前训练重点
中等 · 贪心·invariant
答案摘要
先转成字符串列表,再对字符串列表进行字典序降序排列。最后将列表所有字符串拼接即可。 class Solution:
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题目描述
给定一组非负整数 nums,重新排列每个数的顺序(每个数不可拆分)使之组成一个最大的整数。
注意:输出结果可能非常大,所以你需要返回一个字符串而不是整数。
示例 1:
输入:nums = [10,2]输出:"210"
示例 2:
输入:nums = [3,30,34,5,9]输出:"9534330"
提示:
1 <= nums.length <= 1000 <= nums[i] <= 109
解题思路
方法一:自定义排序
先转成字符串列表,再对字符串列表进行字典序降序排列。最后将列表所有字符串拼接即可。
class Solution:
def largestNumber(self, nums: List[int]) -> str:
nums = [str(v) for v in nums]
nums.sort(key=cmp_to_key(lambda a, b: 1 if a + b < b + a else -1))
return "0" if nums[0] == "0" else "".join(nums)
复杂度分析
| 指标 | 值 |
|---|---|
| 时间 | O(n \log n) |
| 空间 | O(n) |
面试官常问的追问
外企场景- question_mark
Can the candidate efficiently explain why sorting is key in forming the largest number?
- question_mark
Does the candidate address edge cases such as leading zeros or large number sizes?
- question_mark
How well does the candidate handle performance considerations when discussing sorting and comparisons?
常见陷阱
外企场景- error
Overlooking the need for a custom sorting function for concatenation comparisons.
- error
Failing to handle edge cases, especially when all elements are zeros or very large numbers.
- error
Returning an integer instead of a string when the output can be very large.
进阶变体
外企场景- arrow_right_alt
Use a different sorting method such as a priority queue or bucket sort to optimize performance.
- arrow_right_alt
Consider a variation where you need to handle both positive and negative numbers in the input.
- arrow_right_alt
Solve the problem while restricting to a certain time complexity or memory limit.