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区间列表的交集

给定两个由一些 闭区间 组成的列表, firstList 和 secondList ,其中 firstList[i] = [start i , end i ] 而 secondList[j] = [start j , end j ] 。每个区间列表都是成对 不相交 的,并且 已经排序 。 返回这 两…

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中等 · 双·指针·invariant

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答案摘要

class Solution: def intervalIntersection(

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description

题目描述

给定两个由一些 闭区间 组成的列表,firstListsecondList ,其中 firstList[i] = [starti, endi] 而 secondList[j] = [startj, endj] 。每个区间列表都是成对 不相交 的,并且 已经排序

返回这 两个区间列表的交集

形式上,闭区间 [a, b](其中 a <= b)表示实数 x 的集合,而 a <= x <= b

两个闭区间的 交集 是一组实数,要么为空集,要么为闭区间。例如,[1, 3][2, 4] 的交集为 [2, 3]

 

示例 1:

输入:firstList = [[0,2],[5,10],[13,23],[24,25]], secondList = [[1,5],[8,12],[15,24],[25,26]]
输出:[[1,2],[5,5],[8,10],[15,23],[24,24],[25,25]]

示例 2:

输入:firstList = [[1,3],[5,9]], secondList = []
输出:[]

示例 3:

输入:firstList = [], secondList = [[4,8],[10,12]]
输出:[]

示例 4:

输入:firstList = [[1,7]], secondList = [[3,10]]
输出:[[3,7]]

 

提示:

  • 0 <= firstList.length, secondList.length <= 1000
  • firstList.length + secondList.length >= 1
  • 0 <= starti < endi <= 109
  • endi < starti+1
  • 0 <= startj < endj <= 109
  • endj < startj+1
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解题思路

方法一:双指针

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class Solution:
    def intervalIntersection(
        self, firstList: List[List[int]], secondList: List[List[int]]
    ) -> List[List[int]]:
        i = j = 0
        ans = []
        while i < len(firstList) and j < len(secondList):
            s1, e1, s2, e2 = *firstList[i], *secondList[j]
            l, r = max(s1, s2), min(e1, e2)
            if l <= r:
                ans.append([l, r])
            if e1 < e2:
                i += 1
            else:
                j += 1
        return ans
speed

复杂度分析

指标
时间Depends on the final approach
空间Depends on the final approach
psychology

面试官常问的追问

外企场景
  • question_mark

    The candidate understands how to implement a two-pointer technique efficiently.

  • question_mark

    They should be able to explain the trade-off of traversing both lists in a single pass rather than checking each pair of intervals individually.

  • question_mark

    The candidate can identify the necessary conditions for intervals to overlap and the corresponding actions to move the pointers accordingly.

warning

常见陷阱

外企场景
  • error

    Incorrectly handling cases where intervals do not overlap, resulting in missing intersections.

  • error

    Failing to move the correct pointer after finding an intersection, leading to unnecessary comparisons.

  • error

    Not keeping track of the current intersecting range properly, which could lead to incorrect results.

swap_horiz

进阶变体

外企场景
  • arrow_right_alt

    The problem can be extended to find the union of two interval lists instead of the intersection.

  • arrow_right_alt

    A variant could involve unsorted interval lists, requiring sorting before applying the two-pointer technique.

  • arrow_right_alt

    The problem could also ask to handle intervals with more complex ranges, such as half-open intervals.

help

常见问题

外企场景

区间列表的交集题解:双·指针·invariant | LeetCode #986 中等