LeetCode Problem Workspace
Water Bottles II
Compute the maximum number of water bottles you can drink by simulating exchanges with step-by-step math logic.
2
Topics
8
Code langs
3
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Practice Focus
Medium · Math plus Simulation
Answer-first summary
Compute the maximum number of water bottles you can drink by simulating exchanges with step-by-step math logic.
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Start by drinking all full bottles while tracking empty ones. Exchange empty bottles for full ones whenever possible and continue the process until no more exchanges are allowed. This approach guarantees the correct maximum count by simulating each step and applying the exchange logic consistently.
Problem Statement
You have a certain number of full water bottles and a rule to exchange empty bottles for new full ones. Each time you drink a full bottle, it becomes empty, and you can trade a set number of empty bottles for one full bottle.
Given two integers numBottles and numExchange, determine the total number of bottles you can drink. You must simulate the drinking and exchanging process without combining multiple exchanges in one step, ensuring you follow the exact exchange rule at each iteration.
Examples
Example 1
Input: numBottles = 13, numExchange = 6
Output: 15
The table above shows the number of full water bottles, empty water bottles, the value of numExchange, and the number of bottles drunk.
Example 2
Input: numBottles = 10, numExchange = 3
Output: 13
The table above shows the number of full water bottles, empty water bottles, the value of numExchange, and the number of bottles drunk.
Constraints
- 1 <= numBottles <= 100
- 1 <= numExchange <= 100
Solution Approach
Iterative Simulation
Use a loop to drink full bottles and collect empties. After each round, trade every numExchange empty bottles for new full bottles and repeat until no more trades are possible.
Mathematical Shortcut
Recognize that total drinks equal initial bottles plus additional bottles from exchanges. Compute total exchanges by integer division and remainder until empty bottles are insufficient.
Edge Case Handling
Ensure that when empty bottles are fewer than numExchange, no exchange occurs. Avoid attempting multiple exchanges simultaneously, as it violates the problem's simulation pattern.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | Depends on the final approach |
| Space | Depends on the final approach |
Time complexity is O(log(numBottles)) if tracking exchanges iteratively, since each exchange reduces empty bottles. Space complexity is O(1) because only counters for full and empty bottles are maintained.
What Interviewers Usually Probe
- Focus on simulating each exchange step carefully rather than jumping to a formula.
- Check whether edge cases like numBottles < numExchange are handled correctly.
- Watch for infinite loops if empty bottles are not reduced after exchanges.
Common Pitfalls or Variants
Common pitfalls
- Trying to combine multiple exchanges at once instead of following the iterative pattern.
- Forgetting to increment the total drink count after each new full bottle obtained.
- Neglecting the scenario when remaining empty bottles are less than numExchange, causing incorrect loops.
Follow-up variants
- Change numExchange to vary at each step, testing dynamic exchange rates.
- Introduce a limit on total exchanges allowed, requiring careful simulation.
- Start with zero full bottles but some empty bottles to see if exchange logic triggers correctly.
FAQ
What is the main approach for Water Bottles II?
Simulate drinking bottles and exchanging empties step by step, or compute total via repeated integer division for exchanges.
Can multiple exchanges happen in one iteration?
No, each exchange must follow the rule exactly; multiple batch exchanges at once violate the problem's simulation pattern.
What if numBottles is less than numExchange?
You can only drink the existing bottles with no exchange possible, ending the simulation.
Does the problem require tracking empty bottles?
Yes, tracking empties is essential to know when exchanges can occur and calculate the total drinks.
Which pattern is Water Bottles II an example of?
It exemplifies Math plus Simulation, combining iterative exchange calculations with a running total of drinks.
Solution
Solution 1: Simulation
We can drink all the full water bottles at the beginning, so initially the amount of water we drink is $\textit{numBottles}$. Then, we repeatedly perform the following operations:
class Solution:
def maxBottlesDrunk(self, numBottles: int, numExchange: int) -> int:
ans = numBottles
while numBottles >= numExchange:
numBottles -= numExchange
numExchange += 1
ans += 1
numBottles += 1
return ansContinue Topic
math
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Math plus Simulation
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Medium
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