LeetCode Problem Workspace
Maximum Number of Operations With the Same Score II
This problem asks to maximize operations on an integer array where all deletions produce the same score using dynamic programming.
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Practice Focus
Medium · State transition dynamic programming
Answer-first summary
This problem asks to maximize operations on an integer array where all deletions produce the same score using dynamic programming.
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Use state transition dynamic programming to track all possible scores after each operation. Memoization helps avoid recomputation by storing intermediate results. Iterate through pairs and recursively calculate the maximum number of operations that maintain a consistent score across all deletions.
Problem Statement
Given an integer array nums, you can repeatedly remove any two elements while at least two elements remain. Each removal yields a score equal to the sum of the two elements removed.
Determine the maximum number of operations that can be performed such that every operation results in the same score. The order of removal and pair selection affects the total number of valid operations, and dynamic programming is key to exploring all possibilities.
Examples
Example 1
Input: nums = [3,2,1,2,3,4]
Output: 3
We perform the following operations:
- Delete the first two elements, with score 3 + 2 = 5, nums = [1,2,3,4].
- Delete the first and the last elements, with score 1 + 4 = 5, nums = [2,3].
- Delete the first and the last elements, with score 2 + 3 = 5, nums = []. We are unable to perform any more operations as nums is empty.
Example 2
Input: nums = [3,2,6,1,4]
Output: 2
We perform the following operations:
- Delete the first two elements, with score 3 + 2 = 5, nums = [6,1,4].
- Delete the last two elements, with score 1 + 4 = 5, nums = [6]. It can be proven that we can perform at most 2 operations.
Constraints
- 2 <= nums.length <= 2000
- 1 <= nums[i] <= 1000
Solution Approach
Identify all possible scores
First, calculate every possible sum of pairs in nums to establish candidate operation scores. These scores form the basis for state transitions in the dynamic programming solution.
Dynamic programming with memoization
Define a DP state representing the current array configuration and target score. Use memoization to store results for subarrays and partial operations, avoiding repeated calculations of the same state.
Iterative pair selection and recursion
Recursively remove valid pairs matching the target score, updating the array and DP state. Track the number of successful operations and return the maximum count after exploring all removal sequences.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | Depends on the final approach |
| Space | Depends on the final approach |
Time and space complexity depends on the DP implementation. A naive recursive approach may reach O(2^n), but memoization reduces repeated state computations. With optimized DP, expect time O(n^3) in worst case and space O(n^2) for storing subarray results.
What Interviewers Usually Probe
- Focus on state transition dynamic programming with memoization to avoid redundant calculations.
- Consider how pair selection order affects maximum operations with the same score.
- Highlight that after choosing the first operation, the score of subsequent operations is fixed and drives DP decisions.
Common Pitfalls or Variants
Common pitfalls
- Forgetting to fix the score after the first operation, leading to inconsistent totals.
- Not using memoization, which causes timeouts on larger arrays.
- Assuming any pair sum works without verifying it maintains the same score across all operations.
Follow-up variants
- Allow operations that remove more than two elements while keeping the score consistent.
- Count the maximum operations but with a limited number of total deletions.
- Extend to arrays with negative integers and track valid operation sequences.
FAQ
What pattern is used in Maximum Number of Operations With the Same Score II?
State transition dynamic programming is applied to explore all valid pair removals while maintaining the same score.
Can I use a greedy approach for this problem?
A greedy approach often fails because removing the largest pair first may prevent maximizing total operations; DP ensures correctness.
What is the role of memoization here?
Memoization stores results for each subarray and score combination, reducing recomputation and preventing exponential time complexity.
How do I handle arrays where multiple pairs have the same sum?
Consider all pairs as candidates in DP; recursion with memoization ensures all combinations are explored for maximum operations.
What are the constraints to consider in this problem?
Arrays have length 2 to 2000, with element values between 1 and 1000. Efficient DP is needed to handle larger inputs within time limits.
Solution
Solution 1: Memorization Search
There are three possible values for the score $s$, which are $s = nums[0] + nums[1]$, $s = nums[0] + nums[n-1]$, and $s = nums[n-1] + nums[n-2]$. We can perform memorization search for these three cases separately.
class Solution:
def maxOperations(self, nums: List[int]) -> int:
@cache
def dfs(i: int, j: int, s: int) -> int:
if j - i < 1:
return 0
ans = 0
if nums[i] + nums[i + 1] == s:
ans = max(ans, 1 + dfs(i + 2, j, s))
if nums[i] + nums[j] == s:
ans = max(ans, 1 + dfs(i + 1, j - 1, s))
if nums[j - 1] + nums[j] == s:
ans = max(ans, 1 + dfs(i, j - 2, s))
return ans
n = len(nums)
a = dfs(2, n - 1, nums[0] + nums[1])
b = dfs(0, n - 3, nums[-1] + nums[-2])
c = dfs(1, n - 2, nums[0] + nums[-1])
return 1 + max(a, b, c)Continue Topic
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