LeetCode Problem Workspace
Length of the Longest Alphabetical Continuous Substring
Find the length of the longest continuous alphabetical substring from a given string of lowercase letters.
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Practice Focus
Medium · String-driven solution strategy
Answer-first summary
Find the length of the longest continuous alphabetical substring from a given string of lowercase letters.
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To solve the problem, you need to find the longest substring of consecutive characters in alphabetical order. This involves scanning through the string and comparing adjacent characters to determine the longest segment that satisfies this condition.
Problem Statement
You are given a string s consisting of lowercase letters. Your task is to find the length of the longest substring in which the characters appear in alphabetical order. A substring is considered in alphabetical order if each character is followed by the next character in the alphabet.
For example, the substring "abc" is in alphabetical order, but "acb" is not. The input string can vary in length, with up to 100,000 characters. You need to implement an efficient solution that handles the maximum input size within time and space limits.
Examples
Example 1
Input: s = "abacaba"
Output: 2
There are 4 distinct continuous substrings: "a", "b", "c" and "ab". "ab" is the longest continuous substring.
Example 2
Input: s = "abcde"
Output: 5
"abcde" is the longest continuous substring.
Constraints
- 1 <= s.length <= 105
- s consists of only English lowercase letters.
Solution Approach
Iterate Through the String
To identify the longest alphabetical continuous substring, iterate through the string comparing adjacent characters. Keep track of the length of the current continuous substring, and update the maximum length when a new substring starts.
Track Length of Substrings
Maintain two variables: one for the current length of the alphabetical substring and another for the longest length encountered. Reset the current length when the sequence breaks and update the longest length when needed.
Handle Edge Cases
Ensure that single-character substrings or strings with no continuous alphabetical order are handled correctly. A string of length one will have a continuous substring of length one, and the algorithm should be able to handle strings where no characters form an alphabetical sequence.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | Depends on the final approach |
| Space | Depends on the final approach |
The time complexity of the solution is O(n), where n is the length of the input string. This is because we are iterating through the string once. The space complexity is O(1) since we only need a few variables to keep track of the current and longest lengths.
What Interviewers Usually Probe
- Ability to track the longest substring efficiently
- Effective use of variables to maintain substring length
- Clear understanding of edge cases and constraints
Common Pitfalls or Variants
Common pitfalls
- Overcomplicating the problem with unnecessary nested loops
- Not properly handling edge cases such as strings of length one or no alphabetical sequences
- Failure to update the longest substring correctly during iteration
Follow-up variants
- Consider different ways to scan through the string, such as using sliding window techniques
- Extend the problem to handle uppercase letters as well
- Modify the problem to return the actual substring instead of just its length
FAQ
What is the main approach for solving the Length of the Longest Alphabetical Continuous Substring problem?
The key approach is to iterate through the string, comparing adjacent characters, and keep track of the longest continuous substring that appears in alphabetical order.
How do I handle cases where the string is too short for a meaningful alphabetical substring?
In such cases, a single-character string would have the longest alphabetical substring of length 1. Ensure that this edge case is handled.
What happens when no characters form an alphabetical sequence?
If no characters form a continuous alphabetical sequence, each individual character is considered its own substring, and the length of the longest substring will be 1.
How does the problem relate to the string-driven solution strategy?
This problem is a prime example of using a string-driven approach where you manipulate and process a string character by character to identify patterns or substrings.
What is the time complexity of the solution for the Length of the Longest Alphabetical Continuous Substring problem?
The time complexity of the optimal solution is O(n), where n is the length of the string, as we process each character once.
Solution
Solution 1: Single Pass
We can traverse the string $s$ and use a variable $\textit{ans}$ to record the length of the longest lexicographically consecutive substring, and another variable $\textit{cnt}$ to record the length of the current consecutive substring. Initially, $\textit{ans} = \textit{cnt} = 1$.
class Solution:
def longestContinuousSubstring(self, s: str) -> int:
ans = cnt = 1
for x, y in pairwise(map(ord, s)):
if y - x == 1:
cnt += 1
ans = max(ans, cnt)
else:
cnt = 1
return ansContinue Topic
string
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