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Largest Substring Between Two Equal Characters
Find the longest substring between two equal characters using a hash table for optimized performance.
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Practice Focus
Easy · Hash Table plus String
Answer-first summary
Find the longest substring between two equal characters using a hash table for optimized performance.
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The problem asks for the length of the longest substring between two equal characters. Using a hash table, store the first and last positions of characters to efficiently calculate the length of the substring. This approach ensures a time complexity of O(n) while utilizing constant space.
Problem Statement
Given a string s, you need to return the length of the longest substring between two equal characters, excluding the two characters. If no such substring exists, return -1.
A substring is defined as a contiguous sequence of characters within a string. For example, if the string is 'abca', the longest valid substring between equal characters is 'bc'.
Examples
Example 1
Input: s = "aa"
Output: 0
The optimal substring here is an empty substring between the two 'a's.
Example 2
Input: s = "abca"
Output: 2
The optimal substring here is "bc".
Example 3
Input: s = "cbzxy"
Output: -1
There are no characters that appear twice in s.
Constraints
- 1 <= s.length <= 300
- s contains only lowercase English letters.
Solution Approach
Use a Hash Table to Track Character Positions
Iterate through the string, and for each character, check if it has appeared before. If it has, calculate the substring's length by subtracting the first occurrence from the current index, and keep track of the maximum length found. If it hasn't appeared before, store its index in the hash table.
Check for Edge Case: No Repeated Characters
If there are no repeated characters in the string, immediately return -1. This can be determined during the iteration by checking the hash table for the first appearance of each character.
Handle Small Strings Efficiently
For strings with a length of 1 or 2, the answer is straightforward. Return 0 if the two characters are the same, and -1 if they are different.
Complexity Analysis
| Metric | Value |
|---|---|
| Time | O(n) |
| Space | O(1) |
The time complexity of the solution is O(n) since we iterate over the string once. The space complexity is O(1) because the size of the hash table is limited to 26 entries (one for each lowercase English letter).
What Interviewers Usually Probe
- Candidate should demonstrate understanding of hash table usage in strings.
- The candidate should be able to quickly identify when no solution exists.
- A solid candidate would optimize the process by eliminating unnecessary calculations.
Common Pitfalls or Variants
Common pitfalls
- Forgetting to exclude the two equal characters when calculating the substring length.
- Over-complicating the problem by using unnecessary data structures or algorithms.
- Failing to handle edge cases like strings of length 1 or strings with no repeated characters.
Follow-up variants
- What if the string contains uppercase letters? How would you handle it?
- How would this solution scale if the string is a very large dataset (e.g., millions of characters)?
- What if the problem required finding the longest substring between two equal characters of different types (e.g., digits or symbols)?
FAQ
What is the main algorithmic approach for solving Largest Substring Between Two Equal Characters?
The main approach uses a hash table to store the first occurrence of each character, allowing you to calculate the longest substring between equal characters in O(n) time.
Why does the solution to Largest Substring Between Two Equal Characters have O(n) time complexity?
The algorithm only iterates through the string once, and each operation within the loop (checking the hash table, updating the maximum length) takes constant time, resulting in O(n) time complexity.
What should you do if there are no equal characters in the string?
In this case, the solution should immediately return -1, as there is no valid substring between two equal characters.
What is the space complexity of the solution for Largest Substring Between Two Equal Characters?
The space complexity is O(1) because the size of the hash table is constant, limited to the number of distinct lowercase English letters (26).
Can the solution to Largest Substring Between Two Equal Characters be optimized further?
No, the solution is already optimized for time complexity with O(n). Space complexity is also minimal, and there are no unnecessary operations or data structures.
Solution
Solution 1
#### Python3
class Solution:
def maxLengthBetweenEqualCharacters(self, s: str) -> int:
d = {}
ans = -1
for i, c in enumerate(s):
if c in d:
ans = max(ans, i - d[c] - 1)
else:
d[c] = i
return ansContinue Topic
hash table
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