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检查操作是否合法

给你一个下标从 0 开始的 8 x 8 网格 board ,其中 board[r][c] 表示游戏棋盘上的格子 (r, c) 。棋盘上空格用 '.' 表示,白色格子用 'W' 表示,黑色格子用 'B' 表示。 游戏中每次操作步骤为:选择一个空格子,将它变成你正在执行的颜色(要么白色,要么黑色)。但是…

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当前训练重点

中等 · 数组·matrix

bolt

答案摘要

我们枚举所有可能的方向,对于每个方向 $(a, b)$,我们从 $(\textit{rMove}, \textit{cMove})$ 出发,用一个变量 记录我们走过的格子数,如果我们在走的过程中遇到了颜色为 的格子,且 $\textit{cnt} > 1$,那么我们就找到了一个好线段,返回 。 枚举结束后,如果我们没有找到任何好线段,那么返回 。

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题目描述

给你一个下标从 0 开始的 8 x 8 网格 board ,其中 board[r][c] 表示游戏棋盘上的格子 (r, c) 。棋盘上空格用 '.' 表示,白色格子用 'W' 表示,黑色格子用 'B' 表示。

游戏中每次操作步骤为:选择一个空格子,将它变成你正在执行的颜色(要么白色,要么黑色)。但是,合法 操作必须满足:涂色后这个格子是 好线段的一个端点 (好线段可以是水平的,竖直的或者是对角线)。

好线段 指的是一个包含 三个或者更多格子(包含端点格子)的线段,线段两个端点格子为 同一种颜色 ,且中间剩余格子的颜色都为 另一种颜色 (线段上不能有任何空格子)。你可以在下图找到好线段的例子:

给你两个整数 rMove 和 cMove 以及一个字符 color ,表示你正在执行操作的颜色(白或者黑),如果将格子 (rMove, cMove) 变成颜色 color 后,是一个 合法 操作,那么返回 true ,如果不是合法操作返回 false 。

 

示例 1:

输入:board = [[".",".",".","B",".",".",".","."],[".",".",".","W",".",".",".","."],[".",".",".","W",".",".",".","."],[".",".",".","W",".",".",".","."],["W","B","B",".","W","W","W","B"],[".",".",".","B",".",".",".","."],[".",".",".","B",".",".",".","."],[".",".",".","W",".",".",".","."]], rMove = 4, cMove = 3, color = "B"
输出:true
解释:'.','W' 和 'B' 分别用颜色蓝色,白色和黑色表示。格子 (rMove, cMove) 用 'X' 标记。
以选中格子为端点的两个好线段在上图中用红色矩形标注出来了。

示例 2:

输入:board = [[".",".",".",".",".",".",".","."],[".","B",".",".","W",".",".","."],[".",".","W",".",".",".",".","."],[".",".",".","W","B",".",".","."],[".",".",".",".",".",".",".","."],[".",".",".",".","B","W",".","."],[".",".",".",".",".",".","W","."],[".",".",".",".",".",".",".","B"]], rMove = 4, cMove = 4, color = "W"
输出:false
解释:虽然选中格子涂色后,棋盘上产生了好线段,但选中格子是作为中间格子,没有产生以选中格子为端点的好线段。

 

提示:

  • board.length == board[r].length == 8
  • 0 <= rMove, cMove < 8
  • board[rMove][cMove] == '.'
  • color 要么是 'B' 要么是 'W' 。
lightbulb

解题思路

方法一:枚举

我们枚举所有可能的方向,对于每个方向 (a,b)(a, b),我们从 (rMove,cMove)(\textit{rMove}, \textit{cMove}) 出发,用一个变量 cnt\textit{cnt} 记录我们走过的格子数,如果我们在走的过程中遇到了颜色为 color\textit{color} 的格子,且 cnt>1\textit{cnt} > 1,那么我们就找到了一个好线段,返回 true\textit{true}

枚举结束后,如果我们没有找到任何好线段,那么返回 false\textit{false}

时间复杂度 O(m+n)O(m + n),其中 mmboard\textit{board} 的行数,而 nnboard\textit{board} 的列数,本题中 m=n=8m = n = 8。空间复杂度 O(1)O(1)

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class Solution:
    def checkMove(
        self, board: List[List[str]], rMove: int, cMove: int, color: str
    ) -> bool:
        for a in range(-1, 2):
            for b in range(-1, 2):
                if a == 0 and b == 0:
                    continue
                i, j = rMove, cMove
                cnt = 0
                while 0 <= i + a < 8 and 0 <= j + b < 8:
                    cnt += 1
                    i, j = i + a, j + b
                    if cnt > 1 and board[i][j] == color:
                        return True
                    if board[i][j] in (color, "."):
                        break
        return False
speed

复杂度分析

指标
时间complexity is O(1) since the board size is fixed at 8x8 and each direction has at most 7 cells to check. Space complexity is O(1) as only temporary variables are used for direction checks without extra structures.
空间Depends on the final approach
psychology

面试官常问的追问

外企场景
  • question_mark

    Asks if all eight directions are considered for a good line

  • question_mark

    Wants reasoning on why a move is illegal even if it creates a middle line

  • question_mark

    Checks understanding of endpoint vs middle cells in Array plus Matrix pattern

warning

常见陷阱

外企场景
  • error

    Only checking one or two directions instead of all eight

  • error

    Mistaking middle cell placement for endpoint legality

  • error

    Not handling board boundaries correctly when scanning lines

swap_horiz

进阶变体

外企场景
  • arrow_right_alt

    Check if multiple moves are legal in batch

  • arrow_right_alt

    Support boards larger than 8x8 with same good line rules

  • arrow_right_alt

    Determine all legal moves for a given color on the current board

help

常见问题

外企场景

检查操作是否合法题解:数组·matrix | LeetCode #1958 中等